use_ of_ void_ result
This expression has a type of 'void' so its value can't be used.
Description
#
The analyzer produces this diagnostic when it finds an expression whose
type is
void
, and the expression is used in a place where a value is
expected, such as before a member access or on the right-hand side of an
assignment.
Example
#
The following code produces this diagnostic because
f
doesn't produce an
object on which
toString
can be invoked:
void f() {}
void g() {
f().toString();
}
Common fixes
#Either rewrite the code so that the expression has a value or rewrite the code so that it doesn't depend on the value.
Unless stated otherwise, the documentation on this site reflects Dart 3.9.2. Page last updated on 2025-9-1. View source or report an issue.